4p^2-30p-2106=0

Solution for 4p^2-30p-2106=0 equation:

4p^2-30p-2106=0

a = 4; b = -30; c = -2106;
Δ = b2-4ac
Δ = -302-4·4·(-2106)
Δ = 34596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34596}=186$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-186}{2*4}=\frac{-156}{8}
=-19+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+186}{2*4}=\frac{216}{8}
=27
$